Given a
pattern
and a string str
, find if str
follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in
pattern
and a non-empty word in str
.
Examples:
- pattern =
"abba"
, str ="dog cat cat dog"
should return true. - pattern =
"abba"
, str ="dog cat cat fish"
should return false. - pattern =
"aaaa"
, str ="dog cat cat dog"
should return false. - pattern =
"abba"
, str ="dog dog dog dog"
should return false.
Notes:
You may assume
You may assume
pattern
contains only lowercase letters, and str
contains lowercase letters separated by a single space.
Solution 1: Use two hash map, compare last appearance of c and string.
public class Solution {
public boolean wordPattern(String pattern, String str) {
int n=pattern.length();
String[] words=str.split(" ");
if (words.length!=n) return false;
Map<Character,Integer> mapChar=new HashMap<>();
Map<String,Integer> mapStr=new HashMap<>();
for (int i=0; i<n; i++) {
char c=pattern.charAt(i);
String s=words[i];
if (mapChar.containsKey(c)) {
if (mapStr.containsKey(s)) {
if (mapChar.get(c)>mapStr.get(s)) return false;
if (mapChar.get(c)<mapStr.get(s)) return false;
}
else return false;
}
else {
if (mapStr.containsKey(s)) return false;
else {
mapStr.put(s,i);
mapChar.put(c,i);
}
}
}
return true;
}
}
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