2015年11月5日星期四

Leetcode 284 Peeking Iterator

Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next().

Here is an example. Assume that the iterator is initialized to the beginning of the list: [1, 2, 3].
Call next() gets you 1, the first element in the list.
Now you call peek() and it returns 2, the next element. Calling next() after that still return 2.
You call next() the final time and it returns 3, the last element. Calling hasNext() after that should return false.
Solution 1: Use a buffer Integer to store current value for next()
 class PeekingIterator implements Iterator<Integer> {  
   private Integer v=null;  
   private Iterator<Integer> iterator;  
   public PeekingIterator(Iterator<Integer> iterator) {   
     this.iterator=iterator;  
     if (iterator.hasNext()) v=iterator.next();  
   }  
   public Integer peek() {  
     return v;  
   }  
   @Override  
   public Integer next() {  
     Integer res=v;  
     if (iterator.hasNext()) v=iterator.next();  
     else v=null;  
     return res;  
   }  
   @Override  
   public boolean hasNext() {  
     return v!=null;  
   }  
 }  

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