Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).
You may assume that the intervals were initially sorted according to their start times.
Example 1:
Given intervals
Given intervals
[1,3],[6,9]
, insert and merge [2,5]
in as [1,5],[6,9]
.
Example 2:
Given
Given
[1,2],[3,5],[6,7],[8,10],[12,16]
, insert and merge [4,9]
in as [1,2],[3,10],[12,16]
.
This is because the new interval
[4,9]
overlaps with [3,5],[6,7],[8,10]
.
Solution 1: O(n) solution
public class Solution {
public List<Interval> insert(List<Interval> intervals, Interval newInterval) {
int i=0, n=intervals.size();
List<Interval> res=new ArrayList<>();
while (i<n && intervals.get(i).end<newInterval.start) res.add(intervals.get(i++));
while (i<n && intervals.get(i).start<=newInterval.end) {
newInterval.start=Math.min(newInterval.start,intervals.get(i).start);
newInterval.end=Math.max(newInterval.end,intervals.get(i).end);
i++;
}
res.add(newInterval);
while (i<n) res.add(intervals.get(i++));
return res;
}
}
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