2015年9月17日星期四

Leetcode 16 3Sum Closest

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
    For example, given array S = {-1 2 1 -4}, and target = 1.

    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

Solution 1: similar as 15, just need to keep updating res if absolute value of res-target is smaller. Remember to sort the array first.
 public class Solution {  
   public int threeSumClosest(int[] nums, int target) {  
     Arrays.sort(nums);  
     int n=nums.length;  
     int res=0;  
     int min=Integer.MAX_VALUE;  
     for (int i=0; i<n-2; i++) {  
       if (i>0 && nums[i]==nums[i-1]) continue;  
       int lo=i+1, hi=n-1;  
       while (lo<hi) {  
         int sum=nums[i]+nums[lo]+nums[hi];  
         if (sum==target) return target;  
         if (Math.abs(sum-target)<min) {  
           res=sum;  
           min=Math.abs(sum-target);  
         }  
         if (sum>target) hi--;  
         else lo++;  
       }  
     }  
     return res;  
   }  
 }  

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