Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e.,
0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
Solution 1: Binary search, pay attention to termination condition.
public class Solution {
public int findMin(int[] nums) {
int n=nums.length;
int lo=0, hi=n-1;
while (lo<hi) {
int mid=lo+(hi-lo)/2;
if (nums[mid]>nums[hi]) lo=mid+1;//pay attention mid will not equal to hi until finish
else hi=mid;
}
return nums[lo];
}
}
没有评论:
发表评论