Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete at most two transactions.
Note:
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
Solution 1: Use 2 DP arrays, dp1[i] is max profit of [0...i] and dp2[i] is max profit of [i..n-1], then it is convert to one transaction problem.
public class Solution {
public int maxProfit(int[] prices) {
int n=prices.length;
int[] dp1=new int[n];
int[] dp2=new int[n];
int profit=0;
for (int i=0; i<n; i++) {
if (i==0) {
profit=0;
dp1[i]=0;
}
else {
profit=Math.max(0,profit+prices[i]-prices[i-1]);
dp1[i]=Math.max(dp1[i-1],profit);
}
}
for (int i=n-1; i>=0; i--) {
if (i==n-1) {
profit=0;
dp2[i]=0;
}
else {
profit=Math.max(0,profit+prices[i+1]-prices[i]);
dp2[i]=Math.max(dp2[i+1],profit);
}
}
int res=0;
for (int i=0; i<n; i++) res=Math.max(res,dp1[i]+dp2[i]);
return res;
}
}
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