Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
Can you solve it without using extra space?
Solution 1: use fast/slow pointers. If they meet, means there is cycle.
public class Solution {
public boolean hasCycle(ListNode head) {
ListNode fast=head, slow=head;
while (fast!=null && fast.next!=null) {
fast=fast.next.next;
slow=slow.next;
if (fast==slow) return true;
}
return false;
}
}
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